uptownmaker wrote:If we shuffle things around with algebra a bit, we can write
Power = Current x Current x Resistance (P=I^2*R) or
Power = Voltage x Voltage / Resistance (P=V^2/R).
You have a 2A fuse- that fixes the maximum current. Your load is about 2 ohms. Using the equation above, the maximum deliverable power to your wire is
P= I^2*R= 2A * 2A * 2 ohms = 8W.
noise wrote:Why do you choose the current based equation vs. the voltage based equation to calculate the max power?
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